Board Thread:JS Development/@comment-9605025-20191030060753/@comment-33109274-20191207004725

Oh wait, this might explain what I think I'm doing

Senario, 4 parses, maxOutstandingRequests = 2 Parse 1 Cheap fast parse Parse 2 Expensive slow parse Parse 3 Cheap fast parse Parse 4 Cheap fast parse

Without the for: the parse of 2 and 3 will not even start until the expensive 2 parse has completed.

With the for: parses 2 and then parse 3 will be done without waiting for the expensive parse 2 to complete.